Physics - Electric Generators?
The armature of an ac generator is a circular coil with 50 turns and radius 3.0 cm. When the armature rotates at 350 rpm, the amplitude of the emf in the coil is 17.0 V. What is the strength of the magnetic field (assumed to be uniform)?
This is NON-CALCULUS based Physics! Please help me figure out how to solve it! Thx!
Answer by pierrot bules
E = N.n.phi
phi = N.n (t / s) /E
phi= (50.350/60)/ 17
phi= (50 x 5.83) 17
phi =17.1 Wb ( Webers)
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