**At Hoover Dam, the water intakes are effectively about 220 m above the electric generators.?**

At Hoover Dam, the water intakes are effectively about 220 m above the electric generators. How much water must pass through the generators to power 1.8 million 33-W Las Vegas lightbulbs for 6 minutes?

(HINT: This is a conservation of energy problem. All the energy comes from the falling water. Consider the electric generators to be 100% efficient.)

Enter your answer in the format *.**E**.

_______ kg

To imagine how much water this is, recall that 1.0 kg of water occupies a volume of 1.0 liter.

**Best answer:**

*Answer by Pearlsawme*

1kg of water at a height of 200 has a P.E of (mgh) =200*9.8 = 1960 J

If this energy is used for 6 minutes (= 360s) the power is energy /time = 1960 /360

=5.44 W

For a power of 5.44W we need 1kg of water

To have a power of (1.8 million 33-W) we need {1.8 million 33-W/ 5.44W} kg of water.

Calculate the volume.

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